Find the area of the region enclosed by the graph of x^2+y^2=2x-6y+6+14x-14y+28
Simplify as
x^2 -16x + y^2 + 20y = 34 complete the square on x, y
x^2 -16x + 64 + y^2 + 20y + 100 = 34 + 64 + 100
(x - 8)^2 + ( y +10)^2 = 198
This is a circle centered at ( 8 , -10) with r^2 = 198
Area = pi * r^2 = 198 pi
\( x^2+y^2=2x-6y+6+14x-14y+28\)
This is just a circle. i moved the xs and ys to the left and that just moves the circle. the size depends on the constant which is 34. so the area of the circle would be 34pi
+497 
