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Three of the four vertices of a rectangle are $(5, 11)$, $(16, 11)$ and $(16, -2)$. What is the area of the intersection of this rectangular region and the region inside the graph of the equation $(x - 5)^2 + (y + 2)^2 = 9$? Express your answer in terms of $\pi$.

 Dec 11, 2020
 #1
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I assume  that the missing vertex  is  (5,-2)

 

See the gtaph here : 

 

This is just the area of a quarter circle with a  radius of  3......the area  is

 

pi (3)^2/4  =  (9/4) pi  units^2

 

 

cool cool cool

 Dec 11, 2020

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