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The graph of the equation y = Ax^2 + Bx + C , where are A, B, C integers, is shown below. Find A + B + C.

 

 Jul 29, 2022
 #1
avatar+2668 
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When x=0y=0x+0x+7=7, meaning c=7

 

Likewise, when x=6y=36a+6b+7=7, meaning 36a+6b=0

 

When x=3y=9a+3b+7=1, meaning 9a+3b=6

 

So now, we have this system, and we need to solve for a and b: 

 

9a+3b=6

36a+6b=0

 Jul 29, 2022
 #2
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I worked on this one for a while yesterday.....I got the same equations that you did

    results in a = 2/3    and b = -4

       so I do not think this parabola can be written as   ax^2 + bx + c = y         where a, b and c are INTEGERS  ( a = 2/3)

~EP

Guest Jul 30, 2022
 #3
avatar+1166 
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EP's back! 

 

hi, I came here when you were still inactive, but you are legendary, right?

nerdiest  Jul 31, 2022

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