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The graph of the equation y = Ax^2 + Bx + C , where are A, B, C integers, is shown below. Find A + B + C.

 

 Jul 29, 2022
 #1
avatar+2444 
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When \(x = 0\)\(y = 0x + 0x + 7 = 7\), meaning \(c = 7\)

 

Likewise, when \(x = 6\)\(y = 36a + 6b + 7 = 7\), meaning \( 36a + 6b = 0 \)

 

When \(x = 3\)\(y = 9a + 3b + 7 = 1 \), meaning \(9a + 3b = -6\)

 

So now, we have this system, and we need to solve for a and b: 

 

\(9a + 3b = -6\)

\(36a + 6b = 0 \)

 Jul 29, 2022
 #2
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I worked on this one for a while yesterday.....I got the same equations that you did

    results in a = 2/3    and b = -4

       so I do not think this parabola can be written as   ax^2 + bx + c = y         where a, b and c are INTEGERS  ( a = 2/3)

~EP

Guest Jul 30, 2022
 #3
avatar+1132 
+3

EP's back! 

 

hi, I came here when you were still inactive, but you are legendary, right?

nerdiest  Jul 31, 2022

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