The graph of the equation y = Ax^2 + Bx + C , where are A, B, C integers, is shown below. Find A + B + C.

Guest Jul 29, 2022

#1**0 **

When \(x = 0\), \(y = 0x + 0x + 7 = 7\), meaning \(c = 7\)

Likewise, when \(x = 6\), \(y = 36a + 6b + 7 = 7\), meaning \( 36a + 6b = 0 \)

When \(x = 3\), \(y = 9a + 3b + 7 = 1 \), meaning \(9a + 3b = -6\)

So now, we have this system, and we need to solve for a and b:

\(9a + 3b = -6\)

\(36a + 6b = 0 \)

BuilderBoi Jul 29, 2022