What is the y-intercept form for the two points (0, -1) and (3,-2) if their relationship is proportional?
+9465 I think you want the slope-intercept form for the equation of a line that passes through these points.
slope intercept form is: y = mx + b , where " m " is the slope and " b" is the y-intercept.
slope = \(\frac{\text{change in y}}{\text{change in x}}\,=\,\frac{y_2-y_1}{x_2-x_1}\,=\,\frac{-2-(-1)}{3-0}\,=\,\frac{-2+1}{3}\,=\,-\frac13\)
→ m = - \(\frac13\)
Since (0, -1) is a point on the line, we know that when x = 0 , y = -1 . So...
the y-intercept = -1
→ b = -1
So our equation is
y = - \(\frac13\)x - 1
+9465 I think you want the slope-intercept form for the equation of a line that passes through these points.
slope intercept form is: y = mx + b , where " m " is the slope and " b" is the y-intercept.
slope = \(\frac{\text{change in y}}{\text{change in x}}\,=\,\frac{y_2-y_1}{x_2-x_1}\,=\,\frac{-2-(-1)}{3-0}\,=\,\frac{-2+1}{3}\,=\,-\frac13\)
→ m = - \(\frac13\)
Since (0, -1) is a point on the line, we know that when x = 0 , y = -1 . So...
the y-intercept = -1
→ b = -1
So our equation is
y = - \(\frac13\)x - 1
