What is the y-intercept form for the two points (0, -1) and (3,-2) if their relationship is proportional?

Guest Oct 26, 2017

#1**+1 **

I think you want the slope-intercept form for the equation of a line that passes through these points.

slope intercept form is: y = mx + b , where " m " is the slope and " b" is the y-intercept.

slope = \(\frac{\text{change in y}}{\text{change in x}}\,=\,\frac{y_2-y_1}{x_2-x_1}\,=\,\frac{-2-(-1)}{3-0}\,=\,\frac{-2+1}{3}\,=\,-\frac13\)

→ m = - \(\frac13\)

Since (0, -1) is a point on the line, we know that when x = 0 , y = -1 . So...

the y-intercept = -1

→ b = -1

So our equation is

y = - \(\frac13\)x - 1

hectictar Oct 26, 2017

#1**+1 **

Best Answer

I think you want the slope-intercept form for the equation of a line that passes through these points.

slope intercept form is: y = mx + b , where " m " is the slope and " b" is the y-intercept.

slope = \(\frac{\text{change in y}}{\text{change in x}}\,=\,\frac{y_2-y_1}{x_2-x_1}\,=\,\frac{-2-(-1)}{3-0}\,=\,\frac{-2+1}{3}\,=\,-\frac13\)

→ m = - \(\frac13\)

Since (0, -1) is a point on the line, we know that when x = 0 , y = -1 . So...

the y-intercept = -1

→ b = -1

So our equation is

y = - \(\frac13\)x - 1

hectictar Oct 26, 2017