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Find the equation whose graph is a parabola with vertex $(2,4)$, vertical axis of symmetry, and contains the point $(1,1)$. Express your answer in the form "$ax^2+bx+c$".

 Apr 15, 2021

Best Answer 

 #1
avatar+33689 
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Vertex form of parabola 

y = a (x-2)^2 + 4      sub in the point  1,1 to calculat the value of 'a'

1 = a (-1)^2 + 4

-3 = a

 

y = -3 (x-2)^2 + 4

y = -3x^2 + 12x - 8

 Apr 15, 2021
 #1
avatar+33689 
+2
Best Answer

Vertex form of parabola 

y = a (x-2)^2 + 4      sub in the point  1,1 to calculat the value of 'a'

1 = a (-1)^2 + 4

-3 = a

 

y = -3 (x-2)^2 + 4

y = -3x^2 + 12x - 8

ElectricPavlov Apr 15, 2021

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