Given that the point (9,7) is on the graph of y=f(x), there is one point that must be on the graph of y/2= f(x)-3. What is the sum of coordinates of that point?
Whenever (x', y') is a point on y = f(x), it is always true that y' = f(x').
Therefore \(7 = f(9)\).
Now consider the graph of y/2 = f(x) - 3. What happens when we substitute x = 9 on the right-hand side?
\(\dfrac y2 = f(9) - 3 = 7 - 3 = 4\)
Then y = 8.
Therefore, when x = 9, the point where y = 8 is the point lying on the graph of y/2 = f(x) - 3.
The required point is (9, 8). You can proceed to calculate the sum of the coordinates of that point.