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# Graphing question

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Find the area of the region satisfying the inequality x^2 + y^2 <= 4x + 6y+13 + 10x  +2y

May 8, 2022

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When you move every term to the left-hand side, you get $$x^2 + y^2 - 14x - 8y - 13 \leq 0$$.

Complete the squares and you will get $$(x - 7)^2 + (y - 4)^2 \leq 78$$.

So this is actually just the area enclosed by the circle centered at (7, 4) and with radius $$\sqrt{78}$$. Can you take it from here?

May 8, 2022