+635 The graph of $y = ax^2 + bx + c$ has an axis of symmetry of $x = 2.$ If $(4,7)$ lies on the graph, find another point on the graph.
+1926 First, we have the fact that the axis of symmetry as 2.
Since the distance (4, 7) from x = 2 is the same as (?, 7), we can easily find another point.
We find that (4, 7) is two units away from the line x = 2, so we want to find another point that has y value of 7 and is also 2 units away.
We find that (0, 7) matches all these characterisitics, thus being our answer!
Thanks! :)
