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The graph of $y = ax^2 + bx + c$ has an axis of symmetry of $x = 2.$ If $(4,7)$ lies on the graph, find another point on the graph.

 Jun 6, 2024
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First, we have the fact that the axis of symmetry as 2. 

Since the distance (4, 7) from x = 2 is the same as (?, 7), we can easily find another point. 

 

We find that (4, 7) is two units away from the line x = 2, so we want to find another point that has y value of 7 and is also 2 units away. 

 

We find that (0, 7) matches all these characterisitics, thus being our answer!

 

Thanks! :)

 Jun 6, 2024

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