Assume that $f(3) = 4$. Name a point that must be on the graph of $y= 1/5*f(5x + 5) - 5$.
For f(5x+5) to equal 4 we must have 5x+5 = 3, so x = -2/5.
At x = -2/5 we have y = 1/5 * 4 - 5 or y = -21/5
So the point (-2/5, -21/5) is on the graph. (The point can also be expressed as (-0.4, -4.2) )
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