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+2
102
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avatar+451 

Question 1 (a,b,c) are related to the graph above, and 2, 3, and 4 are different questions:

1a) Enter the letters of the points that lie on the line y= 1/2x+3 ( I found points I,E, F what else are there)

1b) Enter the letters of the points that are below the graph of y= -1/3x

1c) Enter the letters of the points that are on the graph of |x| = |y| .

 

2) What are the coordinates of the intersection of the graphs of 3x-y^2=12 and y=-3?

 

3) In which quadrant(s) do the graphs of y=x^2 and y=3x+10 intersect?

 

4) The graphs of these two equations intersect in how many points?

 

x^2+y^2=25

x^2-y^2=3

 Oct 28, 2021
edited by weredumbmaster22  Oct 28, 2021
edited by weredumbmaster22  Oct 28, 2021
 #1
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0

For 1a, the point B also lies on the line y = 1/2*x + 3.

 Oct 28, 2021
 #2
avatar+451 
+1

Find the area of the region bounded by the y-axis,y=6 the line , y=1/2x and the line .

Could you do this?

 Nov 1, 2021
edited by weredumbmaster22  Nov 1, 2021
 #3
avatar+115335 
+1

For question 2) sub y=-3 into the first equation and solve for x

In fact they are all just fairly simple simultaneous equations

 

Please do not post big chunks of homework again.

One post = one question.

 Nov 2, 2021
 #4
avatar+451 
+2

I am sorry.

I have seen people doing that in the past so I thought it would be okay. If you would like I could repost the questions one by one.

I did distribute and got this:

3x-(-3)^2=12

3x+9=12

3x=3

x=1

 

3(1)-y^2=12

3-y^2=12

-y^2=9

What do I do after??????

 Nov 2, 2021
 #5
avatar+115335 
0

ok we are looking at Q2

 

2) What are the coordinates of the intersection of the graphs of 3x-y^2=12 and y=-3?

 

3x-  [(-3)^2]  =12

 

I have done a correction.  Make sure you understand it and take it from there.

Melody  Nov 2, 2021

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