I did this post recently and i think that it is worth preserving.

Warped Tour Girl wrote:Can you explain the grouping method of factoring. Can you describe a scenario when the grouping method would be preferred over other methods and show me an equation in this situation?

I need help with this, if you can please help(:

I think this is what you want

3x+2x = (3+2)x = 5x

yes, I know that you already know that.

Let's take it a step further.

3(x-7)+2(x-7) = (3+2)(x-7)=> 5(x-7)

or

2x(x-7) + 3(x-7) = (2x+3)(x-7)

taking it back a step Lets try factorising

2x2 - 14x + 3x - 21

I can see that it is equal to

=2x(x-7) + 3(x-7)

=(2x+3) (x-7)

The main time I would really use this is when I am factorising quadratics with a leading coefficient greater than 1

For example let's factorise this one.

2x2-11x+5

I have to look for two numbers that multiply to 2 x 5 =10 [Since they multiply to give a pos they must have the same sign ]

and add to -11 [ add to a negative so must both be negative]

-2 and -5 don't work

-1 and -10 work beautifully -1 x -10=10 and -1+-10 = -11

now I have to split the -11x into -1x and -10x

so I have

2x2-1x -10x+5

now I am going to factorise in pairs

x(2x-1) -5( 2x-1)

(x-5)(2x-1)

That is the main time when I would use this technique.

I actually found a video on this just yesterday that I quite like. (all except the man waving his pen around the place )

I'll go see if I can find it.

http://www.youtube.com/watch?v=ZQ-NRsWhOGI

It might be worth a watch.

Warped Tour Girl wrote:Can you explain the grouping method of factoring. Can you describe a scenario when the grouping method would be preferred over other methods and show me an equation in this situation?

I need help with this, if you can please help(:

I think this is what you want

3x+2x = (3+2)x = 5x

yes, I know that you already know that.

Let's take it a step further.

3(x-7)+2(x-7) = (3+2)(x-7)=> 5(x-7)

or

2x(x-7) + 3(x-7) = (2x+3)(x-7)

taking it back a step Lets try factorising

2x2 - 14x + 3x - 21

I can see that it is equal to

=2x(x-7) + 3(x-7)

=(2x+3) (x-7)

The main time I would really use this is when I am factorising quadratics with a leading coefficient greater than 1

For example let's factorise this one.

2x2-11x+5

I have to look for two numbers that multiply to 2 x 5 =10 [Since they multiply to give a pos they must have the same sign ]

and add to -11 [ add to a negative so must both be negative]

-2 and -5 don't work

-1 and -10 work beautifully -1 x -10=10 and -1+-10 = -11

now I have to split the -11x into -1x and -10x

so I have

2x2-1x -10x+5

now I am going to factorise in pairs

x(2x-1) -5( 2x-1)

(x-5)(2x-1)

That is the main time when I would use this technique.

I actually found a video on this just yesterday that I quite like. (all except the man waving his pen around the place )

I'll go see if I can find it.

http://www.youtube.com/watch?v=ZQ-NRsWhOGI

It might be worth a watch.

Melody Feb 10, 2014