+128475 a) We can use the the "tangent-secant' theorem, here.....specifically....
m<BAC = 1/2 (minor arc BC - "x")
14 = 1/2 (112 - x)
28 = 112 - x
x = 112 - 28 = 84°
b) For this one we need to find the measure of minor arc CD ......"y" will be 1/2 of this.....
So we have...(360 - 112 - 84 ) = 164°
And 1/2 of this = 82°
+128475 a) We can use the the "tangent-secant' theorem, here.....specifically....
m<BAC = 1/2 (minor arc BC - "x")
14 = 1/2 (112 - x)
28 = 112 - x
x = 112 - 28 = 84°
b) For this one we need to find the measure of minor arc CD ......"y" will be 1/2 of this.....
So we have...(360 - 112 - 84 ) = 164°
And 1/2 of this = 82°
