guys, please help if you know stuff about azimuth.

Sorry...I mis-calculated  the answer to 28 before...here is the corrected answer...!!!!

OK.....let me see if I can help with 28....but...I'm not promising anything since I'm not too familiar with this

The incline part is easy :

The incline from 0 to 3 = +2 degrees

And the incline from 0 To 5 = +23 degrees

So.....the incline from 3 to 5 should just be the incline at 5 - the incline at 3 =   [23 - 2] degrees =  + 21 degrees

The (measured) distance from 3 to 5 is a little more difficult

If you have had trig.....we can use the Law of Cosines to find this

The (measured) distance from 0 to  3 =  13.6 ft

And the (measured) distance from 0 to 5 = 24.6 ft

And the angle between these two stations is just the positive measure of their difference = [157 - 76] degrees = 81 degrees

So....[close your eyes if you haven't had trig]....the (measured distance) is given by

d = sqrt [ (13.6)^2 + (24.6)^2  - 2(13.6)(24.6)cos(81) ]  = about 26.18 ft = 26.2 ft

Note....this is NOT the same as the horizontal distance......

Hi Lisaseal,

Q26

well look at 0 to 3

13.6 apart

Incline = 2 degrees     that is uphill by 2 degrees

Azimuth = 76 degrees

so 

3  to 0 will be

13.6 apart

decline = 2 degrees     that is       Incline =  -2 degrees

Azimuth (compass direction) = 180+76 degrees = 256 degrees

Question 27

draw the triangle :)

sin76 = h / 13.6

h=13.6*sin76

13.6*sin(76) = 13.1960218773536

The horizontal distance is about 13.2 feet

No. 27 is a little trickier than it might seem.....the horizontal distances from 0  to 3 and from 0 to 5 are not 13.6 ft and 24.6 ft, respectively...

Let's look at  0 to 3

The horizontal distance, d,  can be represented as the adjacent side of a right triangle with a hypotenuse of 13.6 ft and an included angle of 2°...and we have

cos (2°) =  d / 13.6     multiply both sides by 13.6

13.6 cos (2°) = d = about 13.59 ft = 13.6 ft (rounded)....this horizontal distance is almost the same as the measured distance because of the small incline between the two stations

However.....the horizontal distance, d,  between 0 and 5 is quite different from the measured distance....using the same idea as before, we have that

cos (23°) = d / 24.6   multiply both sides by 24.6

24.6 cos (23°) = d = about 22.6 ft.  .......note that the steeper incline makes the measured distance about 2 feet more than the horizontal distance