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Hi! I've tried about eight times on this problem, submitted it, and got all of them wrong. I need help on this. Can someone please explain this problem to me? Thanks! 

 

Six people are sitting around a circular table, and each person has either blue eyes or green eyes. Let $x$ be the number of people sitting next to at least one blue-eyed person, and let $y$ be the number of people sitting next to at least one green-eyed person. How many possible ordered pairs $(x,y)$ are there? (For example, $(x,y) = (6,0)$ if all six people have blue eyes, since all six people are sitting next to a blue-eyed person, and zero people are sitting next to a green-eyed person.)

 

Again, thank you so much.

 

 

(They gave me a hint to use casework, but I'm not quite sure how to use casework here.)

 May 26, 2020
edited by Guest  May 26, 2020
 #1
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https://web2.0calc.com/questions/counting-and-probability-question_3

This is the answer.

This is week 5 problem 2 of the counting probability course for aops right???

 May 29, 2020
 #2
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The answer is not 14. I tried

 May 29, 2020

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