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Quadrilateral $ABCD$ is a square. A circle with center $D$ has arc $AEC$. A circle with center $B$ has arc $AFC$. If $AB = 2$ cm, what is the total number of square centimeters in the football-shaped area of regions II and III combined? Express your answer as a decimal to the nearest tenth.
 

i need some help :( i can provide an image if needed.

 

sorry if it seems like im not trying. i have been stumped on this for a while. thanks in advance :))

 Aug 10, 2021
 #1
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The area is 4*pi - 10, which rounds to 2.6.

 Aug 10, 2021
 #2
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that answer is wrong, sorry :(

 Aug 10, 2021
 #3
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Area = 2(pi - 2)

 Aug 11, 2021

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