What is the value of $(a+b)\sqrt{cd}$ if $a = 2$ , $b = 4$, $c = 3$, and $d = 12$?
We have the equation \((a+b)\sqrt{cd}\)
We have all the dimensions for us to solve the problem.
Plugging in all the numbers given, we get
\((2+4)\sqrt{3(12)}\\ =6\sqrt{36}\\ =6(6)\\ =36\)
So 36 is our final answer.
Thanks! :)
We have the equation \((a+b)\sqrt{cd}\)
We have all the dimensions for us to solve the problem.
Plugging in all the numbers given, we get
\((2+4)\sqrt{3(12)}\\ =6\sqrt{36}\\ =6(6)\\ =36\)
So 36 is our final answer.
Thanks! :)