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What is the value of $(a+b)\sqrt{cd}$ if $a = 2$ , $b = 4$, $c = 3$, and $d = 12$?

 Jun 17, 2024

Best Answer 

 #2
avatar+1252 
+1

We have the equation \((a+b)\sqrt{cd}\)

We have all the dimensions for us to solve the problem. 

 

Plugging in all the numbers given, we get

\((2+4)\sqrt{3(12)}\\ =6\sqrt{36}\\ =6(6)\\ =36\)

 

So 36 is our final answer.

 

Thanks! :)

 Jun 17, 2024
 #1
avatar+764 
-1

a = 2   b = 4   c = 3   d = 12

 

(a+b)\sqrt{cd} = (6 + 6) \sqrt{24} = 24*sqrt(3)

 Jun 17, 2024
 #2
avatar+1252 
+1
Best Answer

We have the equation \((a+b)\sqrt{cd}\)

We have all the dimensions for us to solve the problem. 

 

Plugging in all the numbers given, we get

\((2+4)\sqrt{3(12)}\\ =6\sqrt{36}\\ =6(6)\\ =36\)

 

So 36 is our final answer.

 

Thanks! :)

NotThatSmart Jun 17, 2024

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