+0  
 
0
72
4
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I've tried three answers and they were all wrong please help :/ (incorrect answers: 183, 80, 45^6) :((( TYSM

 

 

Let $A_1 A_2 A_3 \dotsb A_{10}$ be a regular polygon. A rotation centered at $A_1$ with an angle of $\alpha$ takes $A_4$ to $A_8$. Given that $\alpha < 180^\circ$, find $\alpha,$ in degrees.

 

 

T^T thank you all!

 

btw this is NOT hw. It's my practice problems and I missed a class so I am kind of confused on how to do this kind of problem. Again, TYYYY!!

 Jun 12, 2021
 #1
avatar+33689 
+2

SUm of the interior angles of the 10 sided polygon     (n-2)* 180 = 1440 degrees

 

1440/10 = 144 degrees each angle     the external angle is  180 - 144 = 36

 

alpha goes from 4 to 8    or   4 external angles        4 * 36 = 144   degrees

 

 

Here area couple of pictures:

 

 Jun 12, 2021
 #2
avatar
0

that's incorrect... sorry...

 Jun 12, 2021
 #3
avatar+114082 
0

How about saying thanks.

 

EP obviously put a lot of time into your answer.

 

Also, please state why you believe it to be wrong.

Melody  Jun 13, 2021
 #4
avatar+114082 
+1

Here is your answer:

But I would still like you to thanks EP and to answer my question as to why you believed it to be wrong.

Even if it is just that you put it in an answer box and it was wrong.  You should always give your reason.

 

72 degrees clockwise or  360-72 counterclockwise.

But you only want the little one.

 

 Jun 13, 2021

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