I've tried three answers and they were all wrong please help :/ (incorrect answers: 183, 80, 45^6) :((( TYSM
Let $A_1 A_2 A_3 \dotsb A_{10}$ be a regular polygon. A rotation centered at $A_1$ with an angle of $\alpha$ takes $A_4$ to $A_8$. Given that $\alpha < 180^\circ$, find $\alpha,$ in degrees.
T^T thank you all!
btw this is NOT hw. It's my practice problems and I missed a class so I am kind of confused on how to do this kind of problem. Again, TYYYY!!
+36916 SUm of the interior angles of the 10 sided polygon (n-2)* 180 = 1440 degrees
1440/10 = 144 degrees each angle the external angle is 180 - 144 = 36
alpha goes from 4 to 8 or 4 external angles 4 * 36 = 144 degrees
Here area couple of pictures:
+118608 Here is your answer:
But I would still like you to thanks EP and to answer my question as to why you believed it to be wrong.
Even if it is just that you put it in an answer box and it was wrong. You should always give your reason.
72 degrees clockwise or 360-72 counterclockwise.
But you only want the little one.
