I need help ASAP!!!

Assuming that \(y\neq 1/2, \)simplify the expression \(\dfrac{12y^3-6y^2}{2y-1}. \)

Guest Aug 6, 2020

#1**+5 **

Before you look at answer: Try to divide using long division... watch this video for more information: https://www.khanacademy.org/math/algebra-home/alg-polynomials/alg-long-division-of-polynomials/v/dividing-polynomials-1

Tried it already? Now, here is how I did it:

What can you do to 12y^3-6y^2 to make it easier to divide? (*cough* factoring out a 6? *cough*)

So, after I factored out a 6, I got 6*(2y^3-y^2)/(2y-1). This was easy to divide, and I got 6*y^2, which is 6y^2

OR

If you were smart enough to see if right after factoring, you could multiply the bottom by 6. This is 12y-6. Now, the difference between the top and the bottom? y^2. So, you still end up with 6y^2

:)

ilorty Aug 6, 2020