ok:

state the axis of symmetry of the parabola: y=3(x-2)^2-4

also state the vertex, and whether it is a maximum or a minimum, and the y intercept of the parabola and the graph

ProffesorNobody May 30, 2019

#1**+4 **

y = 3(x - 2)^2 - 4

Vertex = (2, - 4)

Axis of symmetry : x = 2

This parabola opens upward....therefore...the vertex is a minimum

y intercept : let x = 0 and we have

y = 3(0-2)^2 - 4 = 3(-2)^2 - 4 = 3(4) - 4 = 12 - 4 = 10

Here's the graph : https://www.desmos.com/calculator/w1tqaeu5yv

CPhill May 31, 2019