+132 Hi, I'm new to this and for some reason, the website isn't letting me response properly. Anyways, here's the link to the topic I posted earlier. I still am struggling because I'm not sure how the Law of Cosines apply. If c^2=a^2 +b^2 -2ab(cosC), then how can I apply that? I tried setting the different terms in the inequality to sides of a triangle and then using the law of cosines, but it just gets messy. Any help would be greatly appreciated. https://web2.0calc.com/questions/precalc_121
+11 Since I'm in 9th grade math, all I know is that c^2=a^2+b^2 is the pythagoreon theorom.
Hope that helps in some way!
+132 Hey Thank you for the response! Yea I was thinking along the lines of that to help cancel the square root, but I just am not sure how to go from there. I labeled a triangle with c= sqrt(a^2 - ab +b^2) b= sqrt(a^2 - ac +c^2) a= sqrt(b^2 + bc +c^2) Then, I tried putting values into the law of cosines and got: c^2= (b^2 + bc +c^2) + (a^2 - ac +c^2) -2(sqrt(b^2 + bc +c^2)*sqrt(a^2 - ac +c^2)) I don't know how this proves anything. I used the triangle inequality theorem to substitute the terms as a, b, and c in triangle ABC with the lower case letters representing the opposite angles.
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