The area of a square equals the square of a length of the side of the square. The perimeter of a square equals the sum of the lengths of all four sides. The sum of the areas of two squares is 65, while the difference in their areas is 33. Find the sum of their perimeters.
+32 If the difference in the areas is 33, then when A is the smaller square's area and B is the larger square's area, then: a+a+33=65, and if you subtract 33 from both sides, you get 2a=32, so the smaller square's area is 16, so therefore the larger square's area is 65-16=49. If you find the square root of the smaller and larger areas, 4 and 7 respectively, you can add 4+4+4+4+7+7+7+7=44.
