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Line $l_1$ represents the graph of $3x + 4y = -14$. Line $l_2$ passes through the point $(-5,7)$, and is perpendicular to line $l_1$. If line $l_2$ represents the graph of $y=mx +b$, then find $m+b$.

 Jul 6, 2020
 #1
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Rewrite l_1 in the form  y = -(3/4)x - 14/4  Its slope is -3/4, which means the slope of a line perpendicular to it has slope m = +4/3.

 

Thus, line L_2 can be written as  y = 4x/3 + b

 

If it goes through point (-5, 7) then we must have  7 = 4*(-5)/3 + b.

 

Can you take it from here?

 Jul 6, 2020

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