Given that $x+y=\frac7{10}$ and $x-y=\frac5{14}$, find the value of $x^2-y^2$, expressed as a common fraction.
Given that \(x+y=\dfrac7{10}\) and \(x-y=\dfrac5{14}\),
find the value of \(x^2-y^2\), expressed as a common fraction.
\(\begin{array}{|rcll|} \hline x^2-y^2 &=& (x+y)(x-y) \\\\ x^2-y^2 &=& \dfrac7{10}*\dfrac5{14} \\\\ \mathbf{x^2-y^2} &=& \mathbf{\dfrac14} \\ \hline \end{array}\)