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# Halp!

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Given that $x+y=\frac7{10}$ and $x-y=\frac5{14}$, find the value of $x^2-y^2$, expressed as a common fraction.

Jul 21, 2020

#1
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Given that $$x+y=\dfrac7{10}$$ and $$x-y=\dfrac5{14}$$,

find the value of $$x^2-y^2$$, expressed as a common fraction.

$$\begin{array}{|rcll|} \hline x^2-y^2 &=& (x+y)(x-y) \\\\ x^2-y^2 &=& \dfrac7{10}*\dfrac5{14} \\\\ \mathbf{x^2-y^2} &=& \mathbf{\dfrac14} \\ \hline \end{array}$$

Jul 22, 2020