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The number of apples that Sophia has is a multiple of $6$. When she sells one apple, the number of apples is a multiple of $n$. If $n$ is a positive integer less than $10$, how many possible values are there for $n$?

 Dec 24, 2020
 #1
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Let the number of apples  = 6a

Let the multiple of n  =  bn

 

So

 

6a  - 1  =  bn 

 

6a  = bn + 1

 

6a  will  always  be an even integer

 

Then  n  cannot  be even   because   then   bn + 1  would be odd 

 

So.....n must  be odd =  1,3,5,7,9

 

 

cool cool cool

 Dec 24, 2020

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