+0  
 
+1
168
1
avatar

The expression $6y^2-y-51$ can be rewritten as $(3Ay+B)(y-C)$, where $A$, $B$, and $C$ are positive integers. Find $(AC)^2-B$.

 Jul 10, 2020
 #1
avatar+1200 
+2

That equals (6y + 17)(y - 3), so then A = 2, B = 17, C = 3, and 6^2-17 = 19.

 

You are very welcome!

:P

 Jul 11, 2020

16 Online Users

avatar