Find the one 10-digit number which uses all 10 digits and has the following characteristics: The leftmost digit is divisible by 1, the leftmost two digits make a number divisible by 2, leftmost three digits form a number divisible by 3, etc. until the entire 10 digit number is divisible by 10.
+357 A B C D E F G H I J
A+B/2= *integer*
A+B+C/3= *integer*
A+B+C+D/4= *integer*
yadda yadda yadda
Because of divisibility rules, J must be 0 due to math being math.
Such is the same for 5, which means that E is 5.
This goes on for quite a bit and frankly it's very time consuming for me to type, and for you to read.
The answer to this annoying question is 3816547290
3/1=3
38/2=19
381/3=127
3816/4=954
38165/5=7633
381654/6=63609
3816547/7=545221
38165472/8=4770684
381654729/9=42406081
3816547290/10=3816547290
Yay!
