+0

# halp

0
50
2
+237

$$The function h(x) is defined as: h(x) = \left\{ \begin{array}{cl} \lfloor 4x \rfloor & \text{if } x \le \pi, \\ 3-x & \text{if }\pi < x \le 5.2, \\ x^2& \text{if }5.2< x. \end{array}\right. Find h(h(\sqrt{2})).$$

I got 32 when I tried to solve this but it was incorrect.. ):

May 6, 2019

#1
+22180
+3

I got 32 when I tried to solve this but it was incorrect.. ):

$$\text{The function h(x) is defined as: h(x) = \left\{ \begin{array}{cl} \lfloor 4x \rfloor & \text{if } x \le \pi, \\ 3-x & \text{if }\pi < x \le 5.2, \\ x^2& \text{if }5.2< x. \end{array}\right. }\\ \text{Find h\Big(h\left(\sqrt{2} \right) \Big).}$$

$$\begin{array}{|rcll|} \hline h\left(\sqrt{2} \right) &=& \lfloor 4\cdot \sqrt{2} \rfloor \\ &=& \lfloor 4\cdot 1.41421356237 \rfloor \\ &=& \lfloor 5.65685424949 \rfloor \\ &=& 5 \\\\ h(5) &=& 3-5 \\ &=& -2 \\\\ \mathbf{h\Big(h\left(\sqrt{2} \right) \Big)} & =& \mathbf{ -2 } \\ \hline \end{array}$$

May 6, 2019
#2
+237
+2

Thanks!

May 6, 2019