HALPP

By the quadratic formula, the solutions are x = -2 - 4i and x = -2 + 4i.

We begin by cross-multiplying: \(2x(x+4) = (x-5)(x+5)\)

We can expand both sides to get: \(2x^2+8x=x^2-25\)

We can move everything to the left-hand side, which gives us: \(x^2+8x+25=0\)

We now have to solve for x using the quadratic formula. 

Can you do it?

Hint: The answer isn't real.