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The ellipse x2+4y2=4 and the hyperbola x2m(y+2)2=1 are tangent. Compute m.

 May 13, 2024
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{x2+4y2=4x2m(y+2)2=1

 

Substituting, 

44y2m(y+2)2=1m(y+2)2+4y23=0(m+4)y2+4my+4m3=0

 

Take Δ=0, we have 

(4m)24(m+4)(4m3)=016m24(4m2+13m12)=052m+48=0m=1213

 May 13, 2024

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