For what value of the constant a does the system of equations below have infinitely many solutions?2x+5y=−8,6x=16+a−15y
In order for a system to have infinitely many solutions, the equations must represent the same coefficients and constants.
We have the equations:
2x + 5y = - 8
6x + 15y = 16 + a
Multiplying the first equation by 3 gives us:
6x + 15y = -24
6x + 15y = 16 + a
In order for this system to have infintely many solutions, 16 + a = -24
This gives us -40 for a.