Loading [MathJax]/jax/output/SVG/jax.js
 
+0  
 
0
286
3
avatar

For what value of the constant a does the system of equations below have infinitely many solutions?2x+5y=8,6x=16+a15y

 Jul 9, 2022
 #1
avatar+289 
0

In order for a system to have infinitely many solutions, the equations must represent the same coefficients and constants. 

We have the equations:

2x + 5y = - 8

6x + 15y = 16 + a

 

Multiplying the first equation by 3 gives us:

6x + 15y = -24

6x + 15y = 16 + a

 

In order for this system to have infintely many solutions, 16 + a = -24

This gives us -40 for a. 

 Jul 9, 2022
 #2
avatar
0

How do you vote up?

 Jul 9, 2022
 #3
avatar+289 
0

Upvoting only works when you are currently logged in, I believe.

But if logged in, you may always hover over the heart next to the post and select either thumbs up or thumbs down. :)

 Jul 9, 2022

0 Online Users