+0  
 
0
72
2
avatar

Compute the value of x such that\(\left(1+\frac{1}{3}+\frac{1}{9}+\frac{1}{27}\cdots\right)\left(1-\frac{1}{3}+\frac{1}{9}-\frac{1}{27}+\cdots\right)=1+\frac{1}{x}+\frac{1}{x^2}+\frac{1}{x^3}+\cdots\)h

 Jun 6, 2020
 #1
avatar
0

Pls note the h at the end is a typo thanks

 Jun 6, 2020
 #2
avatar
0

The first sequence sums up to =3/2
The second sequence sums up to =3/4

3/2 x 3/4 = 9/8

 

These are closed form formulas to sum up the two sequences:

(1 + 1/3 + 1/9 + 1/27 + ...) = sum_(n=1)^∞ 3^(1 - n) = 3/2
(1 - 1/3 + 1/9 - 1/27 + ...) = sum_(n=1)^∞ (-1)^(1 + n) 3^(1 - n) = 3/4

 

The RHS of  1 + 1/x + 1/x^2 + 1/x^3 + 1/x^4 +.... = x /(x - 1)

Solve for x:
x/(x - 1) = 9/8

Multiply both sides by a polynomial to clear fractions.
Cross multiply:
8 x = 9 (x - 1)

Write the linear polynomial on the right hand side in standard form.
Expand out terms of the right hand side:
8 x = 9 x - 9

Isolate x to the left hand side.
Subtract 9 x from both sides:
-x = -9

Solve for x.
Multiply both sides by -1:

x = 9

 Jun 6, 2020

33 Online Users

avatar