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# hard sum

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43
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Compute $$\left \lceil \sqrt{3} \right \rceil + \left \lceil \sqrt{4} \right \rceil + \left \lceil \sqrt{5}\right \rceil +\cdots +\left \lceil \sqrt{83} \right \rceil$$

Aug 5, 2020

### 1+0 Answers

#1
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I'm reading the question as the "ceilings" of the square roots of 3 to 83. If that is correct, then this is what I got:

Sum =(2, 2, 3, 3, 3, 3, 3, 4, 4, 4, 4, 4, 4, 4, 5, 5, 5, 5, 5, 5, 5, 5, 5, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 9, 9, 9, 9, 9, 9, 9, 9, 9, 9, 9, 9, 9, 9, 9, 9, 9, 10, 10) = 542

Aug 5, 2020