Compute \(\left \lceil \sqrt{3} \right \rceil + \left \lceil \sqrt{4} \right \rceil + \left \lceil \sqrt{5}\right \rceil +\cdots +\left \lceil \sqrt{83} \right \rceil\)
I'm reading the question as the "ceilings" of the square roots of 3 to 83. If that is correct, then this is what I got:
Sum =(2, 2, 3, 3, 3, 3, 3, 4, 4, 4, 4, 4, 4, 4, 5, 5, 5, 5, 5, 5, 5, 5, 5, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 9, 9, 9, 9, 9, 9, 9, 9, 9, 9, 9, 9, 9, 9, 9, 9, 9, 10, 10) = 542
