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Triangle ABC has sides a, b, and c, and circumradius R. Prove that

\(b^2 + c^2 >= a^2 - R^2. \)

When does equality occur?

 

 

I haven't been able to do much on this problem but I think that I should use the law of cosines and law of sines in that order. Solutions would be appreciated. Thanks in advance! smiley

 Aug 15, 2020
 #1
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In the triangle, you can write R = (abc)/(4K).  You should then be able to work out the rest.

 Aug 15, 2020
 #2
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I am still relatively new to trig, what is K?

Guest Aug 16, 2020

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