We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive pseudonymised information about your use of our website. cookie policy and privacy policy.
 
+0  
 
0
101
4
avatar+1364 

 

tried figuring this out but I keep getting confused. If someone can explain ? thank you

 Oct 4, 2019
 #1
avatar+104962 
+2

The first  isn't too difficult 

 

We have the form   (x - h)^2  + (y - h)^2  = r^2

 

The center  is ( x , h)    and the radius  =  sqrt (r^2) = r

 

So....we have

 

(x - 2)^2 + (y + 3)^2  = 80   writing this in a slightly different form we have

 

(x - 2)^2  + ( y - (-3) )^2  = 80

 

So.....the center  is   (2, -3)    and the radius  = sqrt (80)  =  sqrt (16 *5)  = 4sqrt (5)

 

 

 

cool cool cool

 Oct 4, 2019
 #3
avatar+1364 
+1

Ths one is really easy! Wow, thanks for yuor help. I will take notes laugh

jjennylove  Oct 4, 2019
 #2
avatar+104962 
+3

The second one requires a little thinking

 

If the center of the circle lies on the line  y = 6x + 2  and the circle is tangent to the x axis  at (-2, 0)  then the the x coordinate of the center of the circle  is at  x = -2

 

So.....the y cordinate of the center  must be y = 6(-2) + 2  =  -10

 

So....the center  is  ( -2, -10)

 

And since this circle is tangent to the x axis......the radius must = 10

 

So.....the equation is   (x + 2)^2 + (y + 10)^2  = 100

 

See the graph here :   https://www.desmos.com/calculator/8abh7hhozi

 

 

cool cool cool

 Oct 4, 2019
 #4
avatar+1364 
+1

Was a bit confusing but I get how you got the answer, desmos helped my understand it more as well. Thanks

jjennylove  Oct 4, 2019

10 Online Users

avatar