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avatar+1992 

 

tried figuring this out but I keep getting confused. If someone can explain ? thank you

 Oct 4, 2019
 #1
avatar+128079 
+2

The first  isn't too difficult 

 

We have the form   (x - h)^2  + (y - h)^2  = r^2

 

The center  is ( x , h)    and the radius  =  sqrt (r^2) = r

 

So....we have

 

(x - 2)^2 + (y + 3)^2  = 80   writing this in a slightly different form we have

 

(x - 2)^2  + ( y - (-3) )^2  = 80

 

So.....the center  is   (2, -3)    and the radius  = sqrt (80)  =  sqrt (16 *5)  = 4sqrt (5)

 

 

 

cool cool cool

 Oct 4, 2019
 #3
avatar+1992 
+1

Ths one is really easy! Wow, thanks for yuor help. I will take notes laugh

jjennylove  Oct 4, 2019
 #2
avatar+128079 
+3

The second one requires a little thinking

 

If the center of the circle lies on the line  y = 6x + 2  and the circle is tangent to the x axis  at (-2, 0)  then the the x coordinate of the center of the circle  is at  x = -2

 

So.....the y cordinate of the center  must be y = 6(-2) + 2  =  -10

 

So....the center  is  ( -2, -10)

 

And since this circle is tangent to the x axis......the radius must = 10

 

So.....the equation is   (x + 2)^2 + (y + 10)^2  = 100

 

See the graph here :   https://www.desmos.com/calculator/8abh7hhozi

 

 

cool cool cool

 Oct 4, 2019
 #4
avatar+1992 
+1

Was a bit confusing but I get how you got the answer, desmos helped my understand it more as well. Thanks

jjennylove  Oct 4, 2019

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