+0

# having some trouble on this one as well,

0
52
5
+1690

having some trouble on this one as well,

thank you in advance!

Mar 4, 2020

### 5+0 Answers

#1
+1690
+1

i think the middle line would be at (0,0.25)?

Mar 4, 2020
#2
+109499
+2

The  midline  is  the   same  as  with  the  "regular"  sine curve....we  would have to have a plus or minus added to  the function to affect the  normal midline of  y  =  0

The only  thing tricky about  this one  is that  it  is  a  "compressed" sine  curve wth  a  "phase shift"

Note that  we  can write  this  in  the following  manner

f(x)  =  sin (2pi ) ( x  - 1/4)

This  says  that  there  are  2pi  periods  in  2pi  rads....so   .....every period = 1 (rad)

Also.....the  regualr  sine curve  is   shifted  1/4  rads  to the right

Look at the regular  sine  curve  and this function on the same graph :

https://www.desmos.com/calculator/itkg2m4xrj

Note  that  the point   (.25,0)  "starts" the  shifted curve  and the point (1.25, 0)  completes  the period......

Also note that  the  curve  is shifted (1/4) rad to the right  of the regular curve

Mar 4, 2020
#3
+1690
+1

ops i head said the midline opposite, I meant to write (0.25,0) , my mistake.

I have though attached what you have explained and created it, is this correct?(:

jjennylove  Mar 4, 2020
#4
+22043
+3

Looks OK    ,  jjl

ElectricPavlov  Mar 5, 2020
#5
+1690
0

thanks!

jjennylove  Mar 5, 2020