If a football is kicked and it is in the air for 9 seconds, how high does it go?
I think this is impossible for people like us. We would need to be a physicist to figure this out...
I have many questions, like how fast the ball goes, when it is at its peak point. Also, we would need to know the force of gravity, and the angle in which it is kicked. This is science...
Assume it starts and ends on the ground. Assume air resistance is negligible. Then half of the time it will be going up and half coming down. When it reaches its peak height it will have a vertical component of velocity of v = 0 m/s. So we can find its initial vertical component of velocity, u, from:
v = u + at where v = 0 m/s, a = -9.8 m/s2 (gravitational acceleration), t = 9/2 s
Knowing u we can now use:
v2 = u2 + 2as to find the peak height, s (metres).
you can use the second equation of motion s= ut+1/2at^2
here consider that the ball was at rest before kicking . and came to rest after comming to ground
and a=10m/s^2 (9.8) BECAUSE IT IS UNDER THE INFLUENCE OF GRAVITY.
this is only true if the ball is kicked vertically upward .
but if the ball was in a projectile motion i.e. in a 2D motion then apply the formula
H =v02sin2 θ/2g
H = maximum height (m)
v0 = initial velocity (m/s)
g = acceleration due to gravity (9.80 m/s2)
θ = angle of the initial velocity from the horizontal plane (radians or degrees).