+0  
 
0
1238
8
avatar+23 

How do I find the height of a triangle without the area??

 

Thanks in advance!!

 

M

Mathew120  Jan 14, 2015

Best Answer 

 #3
avatar+18829 
+10

How do I find the height of a triangle without the area??

$$\boxed{h_c=\dfrac{a*b}{c}}$$

heureka  Jan 15, 2015
Sort: 

8+0 Answers

 #1
avatar+208 
+5
Rampager1998  Jan 14, 2015
 #2
avatar
0

u divide ur answer they gave you by the other amount on the triangle. then divide by 1/2

Guest Jan 14, 2015
 #3
avatar+18829 
+10
Best Answer

How do I find the height of a triangle without the area??

$$\boxed{h_c=\dfrac{a*b}{c}}$$

heureka  Jan 15, 2015
 #4
avatar+91451 
+5

Really Heureka??  

 If I had more time I would try and work out how that could be demonstrated.

I did try a little but I had no success.  

I don't remember seeing anything like it before.   

Can you show me a proof of this?

Melody  Jan 15, 2015
 #5
avatar+26402 
+5

Assuming you know the length of all three sides you could make use of Heron's formula.  If the sides are of length a, b and c, and b is the base then 

 

$$\frac{1}{2}\times b\times h=\sqrt{s(s-a)(s-b)(s-c)}$$

 

where h is the height and s is the semi-perimeter (=(a+b+c)/2).  This can be rearranged to find h.

.

Alan  Jan 15, 2015
 #6
avatar+18829 
+5

See the question was: Height of a right triangle without area :

$$\\(1) \quad Area = \dfrac{h_c*c}{2} \\\\
(2) \quad Area = \dfrac{a*b}{2}\\\\
\dfrac{h_c*c}{2} = \dfrac{a*b}{2} \\\\
h_c*c = a*b \\\\
h_c= \dfrac{a*b}{c} \\\\$$

heureka  Jan 15, 2015
 #7
avatar+91451 
+8

Thanks Heureka,

Sorry I did not notice that we were talking only of right triangles.  

 

In my defence there is no 'right' in the question it is only in the title.   

 

ALSO note:

The height that is being found here is the perpendicular distance from the hypotenuse to the right angle vertex.

Melody  Jan 15, 2015
 #8
avatar+81014 
+5

Here's another proof of this....assuming that "c" is the hypoteneuse and the height is drawn from the right angle to the hypoteneuse ..  so we have

(1/2) ab sin(90)  = (1/2)ch

 ab   = ch

 h  = ab / c

 

CPhill  Jan 17, 2015

18 Online Users

avatar
avatar
avatar
We use cookies to personalise content and ads, to provide social media features and to analyse our traffic. We also share information about your use of our site with our social media, advertising and analytics partners.  See details