How do I find the height of a triangle without the area??
Thanks in advance!!
M
This link might help: http://www.wikihow.com/Find-the-Height-of-a-Triangle
u divide ur answer they gave you by the other amount on the triangle. then divide by 1/2
How do I find the height of a triangle without the area??
$$\boxed{h_c=\dfrac{a*b}{c}}$$
Really Heureka??
If I had more time I would try and work out how that could be demonstrated.
I did try a little but I had no success.
I don't remember seeing anything like it before.
Can you show me a proof of this?
Assuming you know the length of all three sides you could make use of Heron's formula. If the sides are of length a, b and c, and b is the base then
$$\frac{1}{2}\times b\times h=\sqrt{s(s-a)(s-b)(s-c)}$$
where h is the height and s is the semi-perimeter (=(a+b+c)/2). This can be rearranged to find h.
.
See the question was: Height of a right triangle without area :
$$\\(1) \quad Area = \dfrac{h_c*c}{2} \\\\
(2) \quad Area = \dfrac{a*b}{2}\\\\
\dfrac{h_c*c}{2} = \dfrac{a*b}{2} \\\\
h_c*c = a*b \\\\
h_c= \dfrac{a*b}{c} \\\\$$
Thanks Heureka,
Sorry I did not notice that we were talking only of right triangles.
In my defence there is no 'right' in the question it is only in the title.
ALSO note:
The height that is being found here is the perpendicular distance from the hypotenuse to the right angle vertex.