Hello all, I am in 8th grade in algebra 1, and im working on a study plan, Im in desperate need of help, hence my name.
Anyways, heres whats troubling me,
I need to find the vertex of a quadratic function, I understand for the x point it is -b/2a. However, I dont know how to find the y point. Please help ASAP.
This is how:
When you find -b/2a, (I will call that A)
Plug that(A) back to the equation and then you can solve y.
Hello, good luck on your study plan. :))
A tip, find a friend to study with, you're less likely to get distracted if you know that someone is doing it with you.
As for your question, the best way is to plug in -b/(2a) into x.
For example, if I have the parabola x^2 + 8x + 16, you already know the x coordinate is -4. (-b/(2a))
Knowing the x, we can plug that in to find the y.
(-4)^2 + 8(-4) + 16 = 0
So our y coordinate is 0.