+10 An electric motor drives a pump that raises 0.15m3 of water per minute through a vertical height of 35m. Calculate:
A) the power required: 858.37W
B) the power required to drive the pump if it has an efficiency of 72%: 618.03W
C) the line current if the supply voltage to the motor is 220 volts DC:
+36916 If you did the first parts A and B correctly
know that electricl watts = V * I where v = volts I = current
858.37 w = 220 v * I
I = 3.9 amperes
B) If answer A is correct , this should be 858.37/.72 = 1192.2 watts
1192.2 watts = 220 v * I
I = 5.42 amperes
See this question for methodology to check your 'A' answer:
https://web2.0calc.com/questions/any-help-would-be-appreciated-thank-you_1
+36916 It appears you have "A'" correct
B) if the pump is 72 % efficient....it wastes 28% of the power supplied to it to pump the water ( friction/heat noise vibration etc)
.72 x = 858.37
x = power required = 858.37/.72 = 1192.2 watts required if 28% is wasted
+10 Should I show both values for current in my answer or should I pick just one? And thank you for your help.
I have revised my answer for "B"
+36916 I have no idea which current the question is asking about......I assumed both since it did not specify.....
