Hello, I just have one question with three short parts, I was hoping I could recieve some help. I'd appreciate it, thanks. :)

(Thanks so much for your help).

Guest May 26, 2019

edited by
Guest
May 26, 2019

#1**+1 **

Present population =PP

Future population =FP

FP = PP x [1 + R]^N

FP = 400 x [1 + 1.5]^10

**FP = 3,814,697 - populations of weevils after 10 weeks.**

1,000,000 =400 x 2.5^N

2,500 = 2.5^N

N =log(2,500) / log(2.5)

**N = 8.54 - Number of weeks when the population hits 1,000,000.**

Guest May 26, 2019

#2**+1 **

1. A possible formula is

P = 400(2.5)^(N ) where P is the population after N weeks

[ Note 150% actually means that the population increases by 2.5 times every week ]

2. After 10 weeks we have

P = 400(2.5)^ (10) = 400 (2.5)^10 ≈ 3,814,697

3. We need to solve this

1,000,000,000 = 400 (2.5)^(N) divide both sides by 400

2,500,000 = (2,5)^(N ) take the log of both sides

log 2500000 = log 2.5^(N ) and by a log property we can write

log 2500000 = (N ) log2.5 divide both sides by log 2.5

16.077 = N ≈ 16 weeks

CPhill May 26, 2019