Mary draws an equiangular polygon with m sides, and George draws an equiangular polygon with g sides, where m is less than g. If the exterior angle of Mary's polygon is congruent to the interior angle of George's polygon, find g.
help, anyone???
It says, that the exterior angle of a polygon with m sides is equal to a regular polygon with g sides. So,
360m=180(g+2)g
360g=180gm+360m
2g=gm+2m
Factoring out g:
2g−gm=2m
g(2−m)=2m
So therefore, g=2m2−m.
-24
Exterior angle of Mary's polygon = 360 / m
Interior angle of George's polygon = (g - 2)*180 / g
Since these are congruent....then
360 / m = (g - 2) * 180 / g cross - multiply
360g = 180m * (g - 2)
360g = 180 gm - 360m
360m = 180gm - 360g
2m = gm - 2g
2m = g ( m - 2 )
g = 2m / ( m - 2)