+0  
 
+2
31
5
avatar+948 

At the school carnival, the sixth graders are making directional arrows, as shown below.

A polygon shaped like an arrow is shown. The total height of the arrow head and the arrow tail is 9 inches. The base of the arrow tail is 4 inches. The width of the arrow is 6 inches, and the height of the tail of the arrow is 5 inches.

Each arrow is to be painted red. How much area needs to be painted for 1 arrow?

 Mar 15, 2019
 #1
avatar+948 
+1

I have to go to bed so a early thankyou if you answer this question you guys and other peope are awsome......

laugh

 
 Mar 15, 2019
 #2
avatar+411 
0

Am I the only one, or can no one see the image?

 
 Mar 15, 2019
 #3
avatar+99238 
0

I cannot see any image.  :/

 
Melody  Mar 15, 2019
 #4
avatar+98061 
+2

If the height of the arrow head and tail is 9 inches    and the height of the arrow tail is 5 inches, then the height of the arrow itself is  9  - 5  =  4 inches

 

So....the tail of the arrow is a rectangle of 4 inches width and 5 inches height...so....its area is 4 * 5 = 20 in^2

 

And the arrow itself has a base of 6 and a height of 4.....so...its area = (1/2)(6)(4)  = 12 in ^2

 

So....the total  area of the arrow to be painted is   [ 20 + 12 ] in^2  =  32 in^2   [ if we are just painting one side ]

 

Otherwise.....twice this   if both sides are painted   = 64 in^2

 

cool  cool cool

 
 Mar 15, 2019
 #5
avatar+948 
+1

Thankyou 

 
Nickolas  Mar 15, 2019

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