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At the school carnival, the sixth graders are making directional arrows, as shown below.

A polygon shaped like an arrow is shown. The total height of the arrow head and the arrow tail is 9 inches. The base of the arrow tail is 4 inches. The width of the arrow is 6 inches, and the height of the tail of the arrow is 5 inches.

Each arrow is to be painted red. How much area needs to be painted for 1 arrow?

 Mar 15, 2019

I have to go to bed so a early thankyou if you answer this question you guys and other peope are awsome......


 Mar 15, 2019

Am I the only one, or can no one see the image?

 Mar 15, 2019

I cannot see any image.  :/

Melody  Mar 15, 2019

If the height of the arrow head and tail is 9 inches    and the height of the arrow tail is 5 inches, then the height of the arrow itself is  9  - 5  =  4 inches


So....the tail of the arrow is a rectangle of 4 inches width and 5 inches height...so....its area is 4 * 5 = 20 in^2


And the arrow itself has a base of 6 and a height of 4.....so...its area = (1/2)(6)(4)  = 12 in ^2


So....the total  area of the arrow to be painted is   [ 20 + 12 ] in^2  =  32 in^2   [ if we are just painting one side ]


Otherwise.....twice this   if both sides are painted   = 64 in^2


cool  cool cool

 Mar 15, 2019


Nickolas  Mar 15, 2019

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