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Rationalize the denominator of \(\displaystyle \frac{1}{\sqrt{2} + \sqrt{3} + \sqrt{7}}\), and write your answer in the form \( \frac{A\sqrt{2} + B\sqrt{3} + C\sqrt{7} + D\sqrt{E}}{F},\) where everything is in simplest radical form and the fraction is in lowest terms. What is \(A + B + C + D + E + F\)?

 May 15, 2019
 #1
avatar+100519 
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1 (sqrt(2) + sqrt(3) - sqrt(7)

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(sqrt (2) + sqrt(3) + sqrt(7) )  (sqrt(2) + sqrt(3) - sqrt(7))

 

 

(sqrt(2) + sqrt(3) -sqrt(7)

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2 + sqrt(6) - sqrt(14) + sqrt(6) + 3 - sqrt(21) + sqrt(14) + sqrt(21) - 7

 

 

 

sqrt(2) + sqrt(3) - sqrt(7)   (2sqrt(6) + 2)

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(2sqrt(6) - 2) (2sqrt(6) + 2)

 

 

2sqrt(12) + 2sqrt(2) + 2sqrt(18) + 2sqrt(3)  - 2sqrt(42) - 2sqrt(7)

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24  -  4

 

 

2sqrt(12) +2sqrt(2) + 2sqrt(18) + 2sqrt(3) - 2sqrt(42) - 2sqrt(7)

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                 20

 

sqrt(12)  + sqrt(2) + sqrt(18) + sqrt(3) - sqrt(42) - sqrt(7)

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                     10

 

2sqrt(3) + sqrt(2) + 3sqrt(2) + sqrt(3) - sqrt(42) - sqrt (7)

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                          10

 

 

4sqrt(2) + 3sqrt(3) - 1sqrt(7) - 1sqrt(42)

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               10

 

A + B + C + D + E + F  =

 

4 + 3 - 1  - 1 + 42 + 10  =

 

57

 

 

cool cool cool

 
 May 15, 2019

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