Hi AartarikRoy :)
a,b,c are in A.P , a^2,b^2 and c^2 are in H.P. Show that a=b=c.
I had to look up what a Harmonic Progression was - I've never heard the term before.
A Harmonic Progression is a sequence of quantities whose reciprocals are in arithmetical progression (e.g. 1, 1/3, 1/5, 1/7, etc.).
b−a=c−b(1)2b=c+a(1b)4b2=c2+a2+2ac(1c)and1b2−1a2=1c2−1b2(2)2b2=1c2+1a2(2b)2a2c2=a2b2+b2c2(2c)2a2c2=b2(a2+c2)(2d)8a2c2=(c2+a2+2ac)(a2+c2)(3)
Wolfram|Alpha says the only answer to this is that a=c and by substitution b=a=c
http://www.wolframalpha.com/input/?i=8a%5E2c%5E2%3D(c%2Ba)%5E2(c%5E2%2Ba%5E2)
Of hand I do not yet see how to prove this manually. ://