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Help 5

NotSoSmart  Mar 9, 2018
 #1
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Need help

NotSoSmart  Mar 9, 2018
 #2
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+1

5.

 

y =  5/x      4 to the left....3  up   =

 

y  =  5 / (x + 4)  +  3     first answer

 

 

6.....the points of discontinuity  can be found by factoring the denominator 

 

x^2  + 4x  -  5  

 

(x + 5) (x - 1)

 

Setting each factor to 0  and so;ving for  x

 

x + 5  = 0                x - 1  = 0

x  = -5                      x  = 1        these are the discontinuities

 

 

7

 

   x - 5                         x - 5

__________   =       _________

x^2 +4x + 3              (x + 1) ( x + 3)

 

We can see that we will have discontinuities (asymptotes) at  x  = -1  and x  = -3

 

There will be no holes because no factors "cancel" 

 

 

cool cool cool

CPhill  Mar 9, 2018
edited by CPhill  Mar 10, 2018

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