+128408 5.
y = 5/x 4 to the left....3 up =
y = 5 / (x + 4) + 3 first answer
6.....the points of discontinuity can be found by factoring the denominator
x^2 + 4x - 5
(x + 5) (x - 1)
Setting each factor to 0 and so;ving for x
x + 5 = 0 x - 1 = 0
x = -5 x = 1 these are the discontinuities
7
x - 5 x - 5
__________ = _________
x^2 +4x + 3 (x + 1) ( x + 3)
We can see that we will have discontinuities (asymptotes) at x = -1 and x = -3
There will be no holes because no factors "cancel"
