A right pyramid has a square base with perimeter 24 inches. Its apex is 9 inches from each of the other vertices. What is the height of the pyramid from its peak to the center of its square base, in inches?
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24 / 4 = 6 inches - the edge length of the square base
9^2 = 3^2 + Height^2
H^2 = 9^2 - 3^2
H^2 = 72 take the square root of both sides
H = ~8.485 - inches - the height of the pyramid.