A right pyramid has a square base with perimeter 24 inches. Its apex is 9 inches from each of the other vertices. What is the height of the pyramid from its peak to the center of its square base, in inches?

Let us see if I understand your question!

24 / 4 = 6 inches - the edge length of the square base

9^2 = 3^2 + Height^2

H^2 = 9^2 - 3^2

H^2 = 72 take the square root of both sides

H = ~8.485 - inches - the height of the pyramid.

By the same process used in your question here:https://web2.0calc.com/questions/please-help_69323

Height =7.93725 inches.