+0  
 
+2
200
2
avatar+3185 

A right pyramid has a square base with perimeter 24 inches. Its apex is 9 inches from each of the other vertices. What is the height of the pyramid from its peak to the center of its square base, in inches?

tertre  Mar 17, 2018
 #1
avatar
0

Let us see if I understand your question!

 

24 / 4 = 6 inches - the edge length of the square base

9^2 = 3^2 + Height^2

H^2 = 9^2 - 3^2

H^2 = 72     take the square root of both sides

H = ~8.485 - inches - the height of the pyramid.

Guest Mar 18, 2018
 #2
avatar
0

By the same process used in your question here:https://web2.0calc.com/questions/please-help_69323

 

Height =7.93725 inches.

Guest Mar 19, 2018

32 Online Users

avatar
avatar
avatar
avatar

New Privacy Policy

We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive information about your use of our website.
For more information: our cookie policy and privacy policy.