+385 Both $x$ and $y$ are positive real numbers, and the point $(x,y)$ lies on or above both of the lines having equations $2x+5y = 10$ and $3x+4y = 12$. What is the least possible value of $8x+13y$?
+539 With the info, we try to sum the equation to something useful. We turn the lines into inequalities. Adding the first inequality to two times the second gets us
\(8x+13y=(2x+5y)+2(3x+4y)\geq 10+2\cdot 12 = \boxed{34} \)
credit to aops for the solution
