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# help algebra

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Flying against the wind, a jet travels 6930 miles in 9 hours. Flying with the wind, the same jet travels 6060 miles in 6 hours. What is the rate of the jet in still air and what is the rate of the wind?

Aug 23, 2021

#1
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Let a be the speed the jet travels, and let b be the speed the wind travels.

$9(a-b)=6930$

$a-b=\frac{6930}9=770$

$6(a+b)=6060$

$a+b=\frac{6060}6=1010$

$a+b=770$

$a-b=1010$

You can finish the rest :)

Aug 23, 2021
#3
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Should be:  a  -  b ==770

a + b ==1010

Guest Aug 23, 2021
#2
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[6060 / 6  -  6930/9] ==[1010  -  770] / 2 ==120 mph - the rate of the wind.

[1010  +  770] / 2 ==890 mph - speed of the jet in still air.

Aug 23, 2021