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One ordered pair $(a,b)$ satisfies the two equations $ab^4 = 48a^2 b$ and $a^2 b^5 = 6a^3 b$. What is the value of $b$ in this ordered pair? (Note: you may have to use the Tab key to get your cursor into the middle answer box.)

 Mar 17, 2024
 #1
avatar+128794 
+1

ab^4 =  48a^2b     divide through by ab  →     b^3  =  48a     (1)

a^2b^5 = 6a^3b    divide through by a^2b →   b^4 =   6a       (2)

 

Divide (2)  by (1)

 

b =  6/48  =  1/8

 

cool cool cool

 Mar 17, 2024

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