One ordered pair $(a,b)$ satisfies the two equations $ab^4 = 48a^2 b$ and $a^2 b^5 = 6a^3 b$. What is the value of $b$ in this ordered pair? (Note: you may have to use the Tab key to get your cursor into the middle answer box.)
ab^4 = 48a^2b divide through by ab → b^3 = 48a (1)
a^2b^5 = 6a^3b divide through by a^2b → b^4 = 6a (2)
Divide (2) by (1)
b = 6/48 = 1/8
+1725 
