+2668 The first equation:
Subtract 3 from both sides: \(a-3= \sqrt{5a-9}\)
Square both terms: \(a^2-6a+9=5a-9\)
Bring everything to the left-hand side: \(a^2 -11a+18=0\)
Factor: \((a-9)(a-2)=0\)
This means \(a = 2\) or \(a = 9\)
Plugging these in to check, we find that \(\color{brown}\boxed{a=2}\)
Repeat the steps for the 2nd equation, and feel free to ask if you need any help!
